Thursday, April 28, 2016

Elastic Collisions in the LAB Frame

                While riddled with tedious algebra, elastic collision problems are quite simple to solve given the correct procedure.  In fact, there are two ways to solve them: the LAB frame and the CM frame.  The LAB frame refers to the point of view of an observer in a stationary reference frame while the CM frame, or center of mass frame, refers to the point of view of an observer from a frame moving with the center of mass of the colliding particles.  While it is necessary to know something about what happens after the collision in either case, approaching the scenario from the CM frame eliminates linear momentum and does not require solving a system of equations to determine the motion of the system.  In this blog, I will demonstrate the process for solving a system of colliding particles in the LAB frame.
                When taking the LAB frame approach, one must simply formulate and solve the system of equations describing the conservation of energy and linear momentum of the collision.  Consider the collision below.


For this example, we will assume particles of initial masses m1 and m2 and initial velocities u1 and u2.  While these velocities can be vectors in any direction, we will assume u1 and u2 are only along the x axis.  Furthermore, as I previously mentioned, we must know at least one thing about what happens after the collision.  Thus, for this example, we will assume that particle 1 deflects at an angle of θ1.  Next, we will construct our system of conservation equations.  As we know energy and linear momentum must be conserved, we know

and


where v1 and v2 represent the magnitude of the respective particles’ velocities after the collision and θ2 is the scatter angle of the second particle.  The first equation is the conservation of kinetic energy while the second and third equations are the conservation of linear momentum in the x and y coordinates, respectively.  Finally, to determine the two particles’ velocities and particle 2’s scatter angle after the collision, we must simply solve the system of conservation energies.  Applying this technique for the case in which


and 
we find that


and


In the next post, I will demonstrate how to solve this same scenario from the CM frame.

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